PHP获取一年有几周以及每周开始日期和结束日期
这篇文章主要介绍php计算一年有多少周,获取每周开始日期和结束日期,有需要的朋友可以参考一下。
最近接了一个项目,其中有一需求是用php获取一年有几周以及每周开始日期和接触日期。在网上找些资料没有合适的,于是自己做了一份,下面通过两种方式实现PHP获取一年有几周以及每周开始日期和结束日期。
代码一:
- <?php
- header("Content-type:text/html;charset=utf-8");
- date_default_timezone_set("Asia/Shanghai");
- $year = (int)$_GET['year'];
- $week = (int)$_GET['week'];
- $weeks = date("W", mktime(0, 0, 0, 12, 28, $year));
- echo $year . '年一共有' . $weeks . '周<br />';
- if ($week > $weeks || $week <= 0)
- {
- $week = 1;
- }
- if ($week < 10)
- {
- $week = '0' . $week;
- }
- $timestamp['start'] = strtotime($year . 'W' . $week);
- $timestamp['end'] = strtotime('+1 week -1 day', $timestamp['start']);
- echo $year . '年第' . $week . '周开始时间戳:' . $timestamp['start'] . '<br />';
- echo $year . '年第' . $week . '周结束时间戳:' . $timestamp['end'] . '<br />';
- echo $year . '年第' . $week . '周开始日期:' . date("Y-m-d", $timestamp['start']) . '<br />';
- echo $year . '年第' . $week . '周结束日期:' . date("Y-m-d", $timestamp['end']);
- ?>
代码二:
- <?php
- header("Content-type:text/html;charset=utf-8");
- function getIsoWeeksInYear($year)
- {
- $date = new DateTime;
- $date->setISODate($year, 53);
- return ($date->format("W") === "53" ? 53 : 52);
- }
- function weekday($custom_date)
- {
- $week_start = date('d-m-Y', strtotime('this week monday', $custom_date));
- $week_end = date('d-m-Y', strtotime('this week sunday', $custom_date));
- $week_array[0] = $week_start;
- $week_array[1] = $week_end;
- return $week_array;
- }
- echo '<br> Weeks in 2013<br>' . getIsoWeeksInYear(2013);
- $weekday = weekday(strtotime(date('d-m-Y', strtotime('5-8-2013'))));
- echo '<br> 10-8-2013';
- echo '<br>Start: ' . $weekday[0];
- echo '<br>End: ' . $weekday[1];
- ?>
以上本文的全部内容,希望对大家学习PHP获取一年有几周以及每周开始日期和结束日期,有所帮助。